2x^2+2y^2+2z^2-4x+20z=1

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Solution for 2x^2+2y^2+2z^2-4x+20z=1 equation: 


Simplifying
2x2 + 2y2 + 2z2 + -4x + 20z = 1

Reorder the terms:
-4x + 2x2 + 2y2 + 20z + 2z2 = 1

Solving
-4x + 2x2 + 2y2 + 20z + 2z2 = 1

Solving for variable 'x'.

Reorder the terms:
-1 + -4x + 2x2 + 2y2 + 20z + 2z2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -4x + 2x2 + 2y2 + 20z + 2z2 = 0

The solution to this equation could not be determined.

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